Prachi kashyap Asked a Question
January 31, 2022 11:29 ampts 30 pts
Let G be a group with identity e. Let H be an abelian non-trivial proper subgroup of G with the property that HogHg = {e for all geH. If K={g e G :gh = hg for all he H} , then (a) K is a proper subgroup of H (b) H is a proper subgroup of K (c) K = H (d) There exists no abelian subgroup LcG such that K is a proper subgroup of L [2020 2 Marks]
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  • Navdeep goyal 1 thankyou
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