Let s be the bounded surface of the cylinder x + y4 =1 cut by the planes z = 0 and z = 1+x. then the value of the surface integral js 3z*do is equal to (a) 1+ c

Let S be the bounded surface of the cylinder x + y4 =1 cut by the planes z = 0 and z = 1+x. Then the value of the surface integral Js 3z*do is equal to (A) 1+ cos 0)*do (B) Ssin 6 cos 6 (1+ cos 0)de C)s1+2 cos 0)'do (D) sin cos (1 + 2 cos 6) de