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Chakravarthi g s Asked a Question
November 23, 2020 4:24 pmpts 30 pts
Let S be the bounded surface of the cylinder x + y4 =1 cut by the planes z = 0 and z = 1+x. Then the value of the surface integral Js 3z*do is equal to (A) 1+ cos 0)*do (B) Ssin 6 cos 6 (1+ cos 0)de C)s1+2 cos 0)'do (D) sin cos (1 + 2 cos 6) de
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  • Deepak singh Best Answer
    see attached solution option a is correct if any doubt then ask
    • Adobe Scan 23-Nov-2020 (5).pdf
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