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Chakravarthi G S posted an Question
November 23, 2020 • 21:54 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Let s be the bounded surface of the cylinder x + y4 =1 cut by the planes z = 0 and z = 1+x. then the value of the surface integral js 3z*do is equal to (a) 1+ c

Let S be the bounded surface of the cylinder x + y4 =1 cut by the planes z = 0 and z = 1+x. Then the value of the surface integral Js 3z*do is equal to (A) 1+ cos 0)*do (B) Ssin 6 cos 6 (1+ cos 0)de C)s1+2 cos 0)'do (D) sin cos (1 + 2 cos 6) de

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    Deepak singh 1 Best Answer

    see attached solution option a is correct if any doubt then ask

    Adobe Scan 23-Nov-2020 (5).pdf
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