30 points
>
>
Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Mathematics (MA)
Let v, = (1, 0) v, = (1, -1) and v, = (0, 1), then how many linear transformations t: r°r are there such that t(v,) = v t(v,) = v, t(v.) = v, ?
Let v, = (1, 0) v, = (1, -1) and v, = (0, 1), then how many linear transformations T: R°R are there such that T(v,) = V T(V,) = V, T(V.) = v, ?
2 Answer(s)
Answer Now
- 0 Likes
- 5 Comments
- 0 Shares
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Deepak singh 1 Best Answer
see attached
if any doubt please ask
sir actually there 3 basis(v1,v2);[v2,v3];[v3,v1] exist
yes there are three basis {v1,v2,v3} and v2 is combination of v1 and v2
so this set is linearly dependent
and v1 and v2 is basis
there is T:R^2 to R^2
see please
wait
is it true please verify
for express (0,0) the coefficient of v1&v2 may not be zero?
see attached regarding li
see attached regarding basis
see attached regarding v1 and v2
please read all , if doubt ask again please
(v1,v2),(v1,v3)and (v2,v3) these three are linearly independent , having dimension two , so all these three will be basis of R^2
it is true .
so using this we get there linear transformation for each basis
linear transformation will be different according to different basis is not true statement.. transformation is a function from one vector space to other vector space ..
basis is related to vector space which is R^2 here
ok sir