Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Prerna Chaudhary posted an Question
September 06, 2021 • 03:52 am
![]()
30 points
30 points
- IIT JAM
- Mathematics (MA)
Let y(x) be the solution of the differential equation+y= f(), for x 20, y(0) = 0, where f)= { 0sx<1 then yx) = x21 (a) 2(1-e*) when 0 sx<1 and 2(e 1)e whenx21 (
Let y(x) be the solution of the differential equation+y= f(), for x 20, y(0) = 0, where f)= { 0sx<1 Then yx) = x21 (A) 2(1-e*) when 0 Sx<1 and 2(e 1)e whenx21 (B) 2(1-e) when 0 Sx<1 and 0 when x 21 (C) 2(1- e"*) when 0
1 Answer(s)
Answer Now
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Prerna chaudhary 1
correct answer is A
when f(x)=0 then dy/dx+y=0. its so y= ce-x
but how will we find the value of c
put x=1 in first results we get y= 2((1-e-1) using this condition in second we have c=2(e-1)
please solve for c value
check
thank you
we'll come
case second for x>1 so we calculate new intial condition
okay 👌👌