Prerna chaudhary Asked a Question
September 5, 2021 10:22 pmpts 30 pts
Let y(x) be the solution of the differential equation+y= f(), for x 20, y(0) = 0, where f)= { 0sx<1 Then yx) = x21 (A) 2(1-e*) when 0 Sx<1 and 2(e 1)e whenx21 (B) 2(1-e) when 0 Sx<1 and 0 when x 21 (C) 2(1- e"*) when 0
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  • Prerna chaudhary
    correct answer is A
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    Navdeep
    when f(x)=0 then dy/dx+y=0. its so y= ce-x
  • Navdeep Best Answer
    B
    • cropped4815284149566048047.jpg
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