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Imdadul Haque posted an Question
September 22, 2020 • 15:12 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Lkck_compd hoo ny &digmad n n ornd. sdrog tr brnol at i6j0 cm d.

Lkck_compd hoo ny &digmad n N ornd. Sdrog TR brnol at I6J0 Cm d.

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    Dinesh khalmaniya 1 Best Answer

    option D

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    first check the ir signal

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    nearly 1690 cm- is for amide but here amide group is absent so nearly it will be for ketonic group

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    now we will check nmr signals. in option c and d c3 symmetry is present so all benzene Hs are equivalent so given one nmr . while all three CH3 groupa gives one signal in nmr so C and D have 2 signal

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    but in option C there is ester while D it is ketone so option D is correct

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