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Sonu saini
A and A* has same eigen value not same eigen vector.eigen value of A*A is (lemda )2 not mod lemda square hence answer is d
but I think eigen value of A and A^t are same but then the eigen values of AA^t need not to be square of eigen value of A
https://youtu.be/0fbeZr8aGfk
see this attachment
dear Ankur this attachment will help you
counter example