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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Chemistry (CY)
My ans : c) but in answer sheet ans is b) ability the stepwise stability constant in aqueous solution for formation of ion |m(en)(h,0)4l
ability The stepwise stability constant in aqueous solution for formation of ion |M(en)(H,0)4l [M(en),(H,0),1° and [M(en),/* 1for Cu and Ni is given [M(en)(H,O)4" [M(en), (H,O),]* [M(en)1 Cu A Ni (i) y>q (11) 2 () xp (a) Only ) is true (6) (0) and (1) true (c) All true (d) None of these D but
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Priyanshu kumar
http://wwwchem.uwimona.edu.jm/courses/IrvWill.html check this link too for graph
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Priyanshu kumar
check this data
![cropped7228128547165629969.jpg]()
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As copper II has d9 configuration...so due to john tellor distortion there is large difference in value of stepwise stability constant of Cu II and Ni II complexes....The shape becomez distorted octahedral and which is not occurs in nickel II complexes...So this devaition occurs
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got it tejas....please ask if any doubt in this😊
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Suman Kumar Best Answer
Copper has JTD so it can't do chelation with third en
JTD ke karan Cu ke z-axis wale bond lambe honge & x & y axis wale bond chote honge. So it will form distorted octahedral.
But Ni will form perfect octahedral. So it's K3 is High
But Nickel K1 & K2 is smaller than Cu due to JTSE
yes sir I got....