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Santosh behera Asked a Question
January 15, 2021 9:02 ampts 11 pts
n 0gb-logB log2 9.50 n 0. B number of bacteria at the beginning of a time interval b = number of bacteria at the end of the time interval n = number of generations [log (2 x 10) Ilog (300)]/0.301 = (6.30 2.5) / 0.301 12.62 generations ho o COb Tuptuin upluim G t/n = 60 minutes x 2 hours 12.62 generations = 9.50 minutes per generation Contact Us: Website: www.eduncle.comEmail: support@eduncle.com Call Toll Free: 180
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  • Abhishek kumar singh Best Answer
    here is ur answer
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