Nat12. please send the solution to the problem given in the attachment.

by langrange th O(a)|O(G). so O (a)= 1,2,4,6,8,12,24. but given that a¹²≠e and a8≠e .but a≠e. if a²=e then a⁴=a^6=a^8=a12=e which is not possible similarly for 3 hence order of a i...

Check pls...

see this attachment

see this attachment