Shrigandha Asked a Question
October 17, 2021 12:25 pmpts 30 pts
nd, nf For example Screening constant of alkali metals 2 x 0.85 Li 2,1 1.7 8x 0.85 +2x 1 Na 2,8,1 8.8 8x 0.85 + 10 x 1 K 2,8,8,1 16.8 8 x 0.85 + 28 x 1 2.8,18,8,1 Cs 2,8,18,18,8,1 Rb 34.8 8 x 0.85+ 46x1 52.8 Screening Constant in Zn for (a) 4s- electrons, (b) 3d electron Zn (1s) (2s 2p) (3s 3p)3d)10 (4s) (i) 3 a for 4s electrons, a = 10x 1 + 18 x 0.85 + 1 x 0.35 25.65 a for 3d electrons, o = 18 x 1 + 9 x 0.35 21.15 how do this problem
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  • Bhagat singh 1 thankyou
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