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Vaishnavi mishra Asked a Question
December 19, 2021 7:14 pmpts 30 pts
how to approach this type of questionnnnnnnnnnnnnnn
  • 1 Answer(s)
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  • Navdeep goyal 1 thankyou
    C
    • cropped6051683076811270844.jpg
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  • Sai
    option B
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    Vaishnavi mishra
    c is correct
  • Sai
    here it is given that the function is continuous so we only check on 2 points [0,1] i.e 0 and 1 and thus option B
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    Navdeep goyal 1
    here find number of continus function
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