Sudisha Chowdhury posted an Question
August 07, 2020 • 01:31 am 30 points
  • IIT JAM
  • Mathematics (MA)

Nple : evaluate: jisin 2tx| dx. dt ion. let 27tx = t 27 dx = dt dx = - 2 if x = 0t 0;x = 1 t 2t 1 2 i= sint dt sint | dt 2 2t 2t 2t 1 jo sint dt sin t dt e2t 2t

why the integration ( range pi to 2pi) taking negative sign when the mod function is breaking?

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  • Kiran goswami

    because sinx is negative in pi to 2pi. so |sinx|=-sinx

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