Anukruti Asked a Question
July 21, 2020 9:33 ampts 30 pts
the general formula of amphibole mineral is A0-1B2C5T8O22(OH)2 where A,B,C and T are cationic sites with different coordination no A=12,B=6-8,C=6,T=4.The amount of octahedral Al in an amphibole of composition Na0.6Ca2Mg3.8Al3.0Si6.2O22(OH)2 is
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  • Sajan sarthak sahoo Best Answer
    1.8 part will be octahedral
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    Sajan sarthak sahoo
    3-1.8= 1.2 is octahedral aluminium
  • Rahul pandey thankyou
    Total number of tetrahedral cations should be 8. Si will contribute to 6.2 tetrahedral cations. Remaining (8.0-6.2 = 1.8) tetrahedral cations will be contributed by Al. So 1.8 Al w...
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  • Rahul pandey
    Si will purely work as a tetrahedral cation. Al can work as tetrahedral and octahedral cation both. Part of Al (1.8) will be of tetrahedral coordination and remaining (1.2) will be...
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