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Optics why is the intensity of unpolarised light halfed when it passes through polarizer??
Optics why is the intensity of unpolarised light halfed when it passes through polarizer?? I search a lot on quora but I didn't found meaningful so please answer
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Ruby negi
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the unpolarised light passes through the polarizer. let the unpolarised makes an angle theta with the pass axis of Polariser, so after passing through polarizer, the amplitude of Polarised light that came out of Polariser is Acos(theta) [ you already know why this is, this is same as when r vector makes an angle theta with x-axis then the component of r along x-axis is rcos(theta),here amplitude makes angle with pass axis]. so the intensity you get after polariser is average of (Acos(theta))^2[ this is the definition of intensity I=(Amplitude)^2].. and the average value of cos^2(theta) is 1/2 that's why you get intensity (A^2)/2 which we can written as Io/2 where Io is Max intensity... hope you get this..
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Dhairya sharma
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dear se attached.
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Chandra prakash
dear see malus law in attached file... I hope it's helpful for you
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Chandra prakash
dear see attached file... and clear ur concept... accrodinng to Malus law.... intensity half.... I hope you'll have understand it
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Abhishek singh Best Answer
I am trying me best to let you understand as much as I could. Here firstly I have explained how Malus came to a conclusion and proposed Malus law. Then I addressed you questions. go through each and every word and concept. The integration (which is trivial) has been left for you as an excercise. I hope now you are clear about the concept. questions and comments are welcome.
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