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Roni posted an Question
February 02, 2021 • 17:46 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Org please answer my question as soon as possible

org please answer my question as soon as possible \n.........

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  • Amol ashok pawar Best Answer

    consider the effect of the three-membered ring on the relative stability of starting material and product. All three-membered rings are very strained because the bond angles are 60° instead of 109° or 120°. Cyclopropanone is particularly strained because the sp2 carbonyl carbon would like a bond angle of 120° there is 60° of strain.’ In the hydrate that carbon atom is sp3 hybridized and so there is only about ‘49° of strain.’ Not much gain, but the hydrate is more stable than ketone. The second case is totally different. The hydroxy-aldehyde is not strained at all but the hemiacetal has ‘49° of strain’ at each atom. Even without strain, hydrates and hemiacetals are usually less stable than their aldehydes or ketones because one C=O bond is worth more than two C–O bonds. In this case the hemiacetal is even less stable and unlike the cyclopropanone, can escape strain by breaking a C–O ring

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    Dinesh khalmaniya 1 best-answer

    In order to avoid this electrostatic destabilization, such compounds will form a hydrate at the central (the most electrostatically destabilized) carbon. In the hydrated form there is no repulsive partial positive charge on adjacent carbons

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