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Shreyasi majumdar 1 Best Answer
Aldehydes containing no α−H atoms on heating with a concentrated alkali solution (50%)undergo Cannizzaro's reaction. Here, c and d has alpha H. In 2-methylpropanal, due to +I-effect of the two alkyl groups attached to alpha-carbon, the carbanion of 2-methylpropanal is not stable. In other words, instead of forming its carbanion, 2-methylpropanal prefers to undergo nucleophilic attack by OH- ion at the aldehyde leading to the formation of cannizzaro products. So, correct option is d