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Roni 1 Asked a Question
January 31, 2022 1:46 ampts 30 pts
  • IIT JAM
  • Chemistry (CY)

Please answer my questions as soon as possible so ......

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  • Lingareddy 1 Best Answer
    dE×dt =h/4π dE related to width[frequency] dv1/dv2= dt2/dt1 = 0.2/1 = 1:5 option b is correct
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  • Lingareddy 1 thankyou
    dE×dt =h/4π dE related to width[frequency] dv1/dv2= dt2/dt1 = 0.2/1 = 1:5 option b is correct
    Likes(0) Reply(0)
  • Lingareddy 1
    dE×dt =h/4π dE related to width[frequency] dv1/dv2= dt2/dt1 = 0.2/1 = 1:5 option b is correct
    Likes(0) Reply(0)
  • Lingareddy 1
    dE×dt =h/4π dE related to width[frequency] dv1/dv2= dt2/dt1 = 0.2/1 = 1:5 option b is correct
    Likes(0) Reply(0)
  • Lingareddy 1
    dE×dt =h/4π dE related to width[frequency] dv1/dv2= dt2/dt1 = 0.2/1 = 1:5 option b is correct
    Likes(0) Reply(0)
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