IIT JAM
Amana shiyas Asked a Question
December 12, 2020 9:47 ampts 20 pts
  • IIT JAM
  • Chemistry (CY)

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  • Amana shiyas
    thank you for your answer sir
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  • Lingareddy 1 Best Answer
    Fe+3 /Fe+2 E=0.77 Fe+2/fe E=-0.44 Fe+3/fe E=? dG=dG1+dG2 -nfE=nfE1+nfE2 nE=nE1+nE2 3×E=0.77+2×( -0.44) E=-0.11/3 E= -0.036
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