Supriya posted an Question
February 24, 2021 • 04:39 am 30 points
  • IIT JAM
  • Chemistry (CY)

Please can i get the detailed answer.

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    Priyanshu kumar Best Answer

    Cr(OH)3(s) +IO3(-)(aq) -->CrO4(-2)(aq) + I(-)(aq) remember in basic medium firstbalancing of oxidation number then balancing of O atom.Balancing of O atom is made by using H2O and OH- ions add desired molecules of H2o on the side rich in O atoms and double OH- on oppsite side Cr+3 ---CrO42- Cr+3 + 8OH- ----------CrO42- +3e- +4H2O 3H2O +6E- +IO3- ---------I- +6OH- Balance 2Cr(OH)3 + IO3- + 4 OH- --> 2 CrO4(2)- + I- + 5H2O Ratio of b:a=1:2

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    Thankyou so much.

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