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Reshav posted an Question
September 07, 2020 ā€¢ 23:24 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Please explain the boxed line in the image which formula is it?

thook of Physical Chemistry CELLANEOUS NUMERICALs Ongmole of steam is condensed reversibly to liquid water at 373 K and 101.325 kPa ressure Ahe heat of vaporization of water is 2.256 8 kJ g. Assuming that the steam behaves as an ideal gas, calculate w, q, A,U, A,S, A,A and A,G for the condensation process. The process is H,O(g. 101.325 kPa, 373 K) H,O(1, 101.325 kPa, 373 K) and AvapH (2.256 8 kJ g) (18 g mol) = 40.624 kJ mol Since the process takes place at constant pressure, therefore 9p-AvapH=- 40.624 kJ mol w =- p AV=- p(m,1 m, g p(Vmg where m.e is the molar volume of the gas at 373 K. Hence w = (101.325 kPa) {22.414 dm mol) (373 K/273K)} = 3 103.0 kPa dm' mol = 3 103 J mol A H= q, =- 40.622 4 kJ mol 40 622.4 J mol AS=- =-108.907 J K'mol 373 K A,G =0 A,G = AA+(Av )RT, we have Since AA =- (Av)RT= ---1) (8.314 J K mol) (373 K) = 3 101 J mol A,U= q +w = - 40.622 4 kJ mol+3.101 kJ mol=- 37.52 kJ molr

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    Priyanshu kumar Best Answer

    Reshav It is PV formula only...nothing new

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    TheĀ molar volumeĀ of a gas is theĀ volumeĀ of one mole of a gas at STP. At STP, one mole (6.02 Ɨ 1023Ā representative particles) of any gas occupies aĀ volumeĀ ofĀ 22.4Ā L . A mole of any gas occupiesĀ 22.4Ā L at standard temperature and pressure (0Ā°C and 1 atm).

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    So molar volume at 273 K is 22.414 ...you have to find hera molar volume at 373K..so just by unitary method it is calculated here

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    Now got this??

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    But you can also calculate work here by direct formula -delng*R*T...same answer comes

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