Shruti posted an Question
September 08, 2020 • 21:47 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Please explain this

For which of the following reactions equilibrium constant (k) is less than unity? (a) (CD,JC-H+ (CH),C (CD,,c° (CH,C-H CH, + CH (b) () CH-C=C-H + NH, NH EM +NH, +NH (d)

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  • Narayanarao gundoju best-answer

    dueterated 3°C is less stable than undutersted 3° C so k less than 1 and cyclo heptatriene anion is less stable due to anti aromatic In this case also k is less than 1

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    Priyanshu kumar

    Option A is correct

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    If the value of K is greater than 1, the products in the reaction are favored; if the value of K is less than 1, the reactants in the reaction are favored; if K is equal to 1, neither reactants nor products are favored

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    In option in product side aromatic compound is formed..so product is favoured means K>1...so this is wrong

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    In option B also product is favoured so K>1...as here cyclohepta trienyl cation is formed in product side which is aromatic

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    In option A reactants side is favoured....as the hyperconjugation of CH3 is more than CD3...so reactant side carbocation is more stable than product side...so K<1..means less than unity...So this option is correct

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    In option C also the product side is favourable as acetylide anion is more stable as negative charge is more stable in sp orbital...more s character...so K>1

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    got this shruti??

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    please ask if still any doubt left

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    answer ko mark kr do shruti

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