Aditi agrawal Asked a Question
June 1, 2020 5:37 pmpts 30 pts
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  • Ruby negi
    n(n+1)/2 are the no of distinct elements in the symmteric matrix as you know aij=aji(ex: a12=a21) .... hope you get to know ...
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    Ruby negi
    so (n^2-n)/2 no of elements are repeat itself. so distinct elements are n(diagonal elements)+(n^2-n)/2....
  • Ruby negi Best Answer
    go through this...
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    Abhishek singh
    Nice explaintion!
  • Vaishnavi rajora
    dear u have to memorise properties of matrix to solve the questions. these are thumb rules of matrix algebra
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  • Vaishnavi rajora
    if we have n×n matrix..... dear then u can try that we always have n(n+1)/2 no of elements. bcoz off digonal have same no of elements so we divide it by 2
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  • Vaishnavi rajora thankyou
    if we have n×n matrix we would have n diagonal elements due to n raws
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    Aditi agrawal
    for what it is used
  • Vaishnavi rajora thankyou
    dear this is the property which we proved.....u have to memorise it
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