IIT JAM
Vijay Dalakoti Asked a Question
January 11, 2021 8:45 pmpts 30 pts
  • IIT JAM
  • Physics (PH)

Please explain where i made mistake...i'm unable to find.

30 31 Hind binding enungy pen nucleon in Ne 20 15 10 Ne BE per mucleon = Amp t Nmn m1o Ne) q31 Mey 10 10 X mpt10 mn m(j Ne)|e131 Mey/u 11 lo(mp+ mn) 19-99 2 93 Mey/w 12 10( L-DOT +1-008) - 19.999) 13 Meyhu (8O15 XI0- 19-992)93/ MeY/u A015-19992) x931 Mey 147-098 MeY qivCh ans. 8.03 Mev
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  • Rohit kumar gupta thankyou
    just add the mass energy of total eletron energy too and the devide by 20 then u will get BE per nucleon see the attachment
    • cropped4042041786057222250.jpg
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  • Dhairya sharma Best Answer
    see attached for solution
    • cropped3248017652833480210.jpg
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    Dhairya sharma
    hope it'll help you
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