Vijay posted an Question
January 12, 2021 • 02:15 am 30 points
  • IIT JAM
  • Physics (PH)

Please explain where i made mistake...i'm unable to find.

30 31 Hind binding enungy pen nucleon in Ne 20 15 10 Ne BE per mucleon = Amp t Nmn m1o Ne) q31 Mey 10 10 X mpt10 mn m(j Ne)|e131 Mey/u 11 lo(mp+ mn) 19-99 2 93 Mey/w 12 10( L-DOT +1-008) - 19.999) 13 Meyhu (8O15 XI0- 19-992)93/ MeY/u A015-19992) x931 Mey 147-098 MeY qivCh ans. 8.03 Mev

2 Answer(s) Answer Now
  • 0 Likes
  • 2 Comments
  • 0 Shares
  • Rohit kumar gupta best-answer

    just add the mass energy of total eletron energy too and the devide by 20 then u will get BE per nucleon see the attachment

    cropped4042041786057222250.jpg
whatsapp-btn

Do You Want Better RANK in Your Exam?

Start Your Preparations with Eduncle’s FREE Study Material

  • Updated Syllabus, Paper Pattern & Full Exam Details
  • Sample Theory of Most Important Topic
  • Model Test Paper with Detailed Solutions
  • Last 5 Years Question Papers & Answers