Vijay Dalakoti Asked a Question
January 11, 2022 7:17 pmpts 30 pts
A particle of mass m and energy E is incident on the following 1-D potential 0 for x<0 V(x)={V for 0 L The minimum value of E for which reflection coefficient will be zero, is h2 V+ mL O O V+ 2mL O h2 V+ 4mL O h V+ 8mL The reflection co-eficient becomes zero for energies of the form: nh E, = Vo + 8m? =,2, 3,... h Therefore, the minmm value is. E = Vo+ SmL
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  • Bidyut sinha thankyou
    please see attached picture.
    • cropped1135112557.jpg
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