Vijay posted an Question
January 12, 2022 • 00:47 am 30 points
  • IIT JAM
  • Physics (PH)

Please prove the solution part? how did that expression came? en=v0+n2h2/8ml2?

A particle of mass m and energy E is incident on the following 1-D potential 0 for x<0 V(x)={V for 0 L The minimum value of E for which reflection coefficient will be zero, is h2 V+ mL O O V+ 2mL O h2 V+ 4mL O h V+ 8mL The reflection co-eficient becomes zero for energies of the form: nh E, = Vo + 8m? =,2, 3,... h Therefore, the minmm value is. E = Vo+ SmL

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