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Vijay posted an Question
March 12, 2021 • 23:08 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Please send the solution to the problem given in the attachment.

please send the solution to the problem given in the attachment.

2 Answer(s) Answer Now
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    Deepak singh 1 Best Answer

    p divides n e.g. a6 =2 because 2|6 and 3|6 but the least prime is 2, therefore a6=2 , for a(15) i.e. 15th term of sequence, 3|15 and 5|15, but least prime is 3, therefore a(15)=3 . In this way we get only primes in sequence . Hence limit point will be all prime numbers .

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    Deepak sir, your writing 📝 has cleared my doubt but still I have one doubt that is why have you considered 🤔 two consecutive prime numbers( in the 2nd & '4-5'th lines)?

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    no, I have not considered any consecutivness , I have just take example randomly . In this way there will be infinite primes which are limit point .

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    okay sir!

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