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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Deepak singh 1
Refer attached answer is 8a^2
sir, why didn't you consider the -ve part of the surface?
we have calculated on first octant (all +ve) , then we multiplied by 8 to consider all 8 octants . -ve part of surface has been already included in 8 octants.
but sir how do I know that the intersection part covers some portion in all 8 octants?