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Vijay posted an Question
April 29, 2021 • 19:35 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Please send the solution to the problem given in the attachment

please send the solution to the problem given in the attachment

3 Answer(s) Answer Now
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    Aman kumar yadav best-answer

    Have a look.... White line is x^3 and blue line is inverse of x^3 , i.e x ^1/3 .

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    doubt

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    inverse calculate karne k liye variables change kar sakte hai.

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    agar ni karna chaho to bhi koi problem ni hai. bas last me f-(x) = function of x , me hi likhna.

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    Deepak singh 1 Best Answer

    inverse of x^3 = x^(1/3) . It will exist or not will depends on Domain .

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    what type of inverse is that?

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    Here I have taken Domain=R to codomain R

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    if we take domain N (natural no.) and codomain R then inverse not exist

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    but for inverse only one one condition is sufficient

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    no , its absolutely incorrect .

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    there may be some restrictions here ..

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    Alka ma'am sent me

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    There may be some restrictions . Ask her to send complete image and then read..

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    so acc . to you if bijective then inverse exists, right?

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    yes , see my above counter example .

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    you say this is absolutely incorrect....ok.... could you plz tell me correct definition of inverse/invertible function

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    and remember not give any example ....only definition

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    and one more thing....you say there is some restrictions....so also tell about that restrictions

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    see , from class 12 NCERT book

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    if your definition is correct then disprove my above counter example .

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    you have send , then you will tell restrictions .. send me link from where you found this ... I will check ..

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    see your NCERT above statement also what they say....if there exist a function g such that gof and fog are identity function

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    most correct definition of inverse function is this....

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    your counter example answer

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    see it's definition in any standard differential calculus book not in NCERT

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    my definition is for codomain . Your definition is restricted to range . If we restrict codomain to range then we can absolutely say that inverse function exist for restricted function . But what about codomain ?

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    conclusion is that , 1-1 , onto condition is necessary for function to be invertible . (from your definition also )

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