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Vijay posted an Question

May 27, 2021 • 20:19 pm

30 points

IIT JAM
Mathematics (MA)

Please send the solution to the problem given in the attachment.

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Sankit das

#Vijay Singh Chauhan . First of all the questions is at how many values of x satisfy that x = cosx between 0 to pi . So I was asking what's the value of that x and second point is that if we merge to different eq. i.e. x and cosx and if they are not equal to each other or if x can take any real values i.e. f (x) = x - cosx is unrestricted between 0 and pi then it will look like this and it's a bijective function . But if we restricted the values of x between 0 and pi so u can look at this graph given below it's a function and of course it has one solution between 0 and pi such that x = cosx as u can see in the graph !!!! So main point is that it's a bijective function
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Sankit das

it should intersect at this point
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Sankit das

Can u plz tell us that what is the value of the x for which it obey the eq. x - cosx
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see
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Deepak singh 1 Best Answer

Refer attached option b is correct
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sir can we solve by graph like this...
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yes , we can solve in this way also..
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ok sir thank u
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Anku don't you think your y=x graph is wronng?
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doubt
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If a continuous function has values of opposite sign inside an interval, then it has a root in that interval .
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graph will look like this .
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its defintion of roots .
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doubt
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