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Alka gupta Best Answer
see...
please only answer what is being asked.
your ans is also there....and I want to tell you why we are writing an = x^2n/(2n)^p
why case 1 is wronng?
in case one you skip x^2n....and convergence divergence depands on x....if we are not consider this then we can not say anything about convergence or divergence....so that's why case first is wrong