Please solve it...

according to this when the capacitor is fully charged the current in the circuit is zero

is it correct

it's like that.....when capacitor is fully charged it accommodate maximum charge and we will remove the voltage source from here bcoz we don't neee it now. and capacitor will start discharging.

so during discharging the current flow.will be equal to what you have derived do you want to say this

means when we removw the voltage source then capacitor behaves as voltage source

am i right

exactly....basically current means what....rate of flow of charges...... so it would be same in both situation

the rate at which charge accommodate will be same as charge decreasing.

i am accepting your answers. just i was clearing my doubts and hey are cleared noe

thanks

dear just clear your whole doubts..... it's really good.

m here for helping you

ok

most welcome dear.......plz ask ur doubts if u have.

no they are cleared

happy to help u dear

see dear

can you provide the derivation of the first equation you have used

yes dear......i hv attached plz see that

what do you mean by current flow by charging capacitor

when we are adding voltage source first chage will accommodate in capacitor

yes then after that the capacitor will discharge so what will be its equation

ok

m attaching see that