Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Raghav Khanna
sir in part (vii), for 1/(log n)^p is convergent when p>1, but p must be constant wrt n, as n tends to infinity. But here, p=log n which itself varies with n. Then how can you use the series sigma(1/(logn)^p) here?