Raghav posted an Question
June 15, 2022 • 22:21 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Please solve part (iv) and (vii)

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  • Raghav Khanna

    sir in part (vii), for 1/(log n)^p is convergent when p>1, but p must be constant wrt n, as n tends to infinity. But here, p=log n which itself varies with n. Then how can you use the series sigma(1/(logn)^p) here?

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