IIT JAM
Shib sagar Asked a Question
August 24, 2020 4:03 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

Please solve these questions

ksmsm jsksks. jskssl > VO d) VO> TiO> MnO0> CaO 98.
  • 2 Answer(s)
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  • Anonymous User Best Answer
    Q 96 option C is correct
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    Anonymous User
    Flourine is a weak ligand
  • Priyanshu kumar thankyou
    96 ...Option C is correct.. Fluorine is a weak field ligand so it's CFSE value is less.
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    Priyanshu kumar
    For 97 option D is correct
    • cropped5371383231176354884.jpg
  • Anonymous User
    Q95 option B is correct
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    Anonymous User
    Co³+ d6 configuration so it will have very CFSE. So it normal spinel
  • Anonymous User
    Q 97 option D is correct
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    Anonymous User
    Ca ²+. is d⁰ configuration so zero CFSE. Mn²+ has also zero CFSE as it d5 configuration.
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