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Aditi agrawal Asked a Question
July 8, 2020 6:36 pmpts 30 pts
fz 1, prove that ) is a pure imaginary number, what will you conclude, if Z+T : = 1? Ans. If : = 1, 0, which is purely real.
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  • Deepak singh Best Answer
    see attached
    • cropped804834666.jpg
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    Deepak singh
    see proof
  • Vaishali sharma thankyou
    see
    • cropped6913006133990978742.jpg
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    Vaishali sharma
    proof
  • Vaishali sharma
    dear if z = 1 then numerator will 0 and it's real no.
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    Aditi agrawal
    ok thanks
  • Deepak singh
    if z= 1 , it will be zero
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    Deepak singh
    see attached above
  • Ravi prakash yadav
    Put (z-1)/(z+1)=t and then rearrange it as z=(1+t)/(1-t). then equate mod(z)=1 Solve for t. see the attached solution for better understanding
    • cropped4407870893612567384.jpg
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