Shweta Thakur posted an Question
June 30, 2020 • 14:40 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Please tell that in enthalpy of neutralization for hf +naoh is greater than 57.1 ki/equi. ...although hf us strong acid and naoh is strong base.... why????

please tell that in enthalpy of neutralization for HF +naoh is greater than 57.1 ki/equi.

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  • Suman Kumar best-answer

    Most weak acids have larger anions that probably are more weakly solvated but F- is a much smaller anion so it will be more strongly solvated. This seems to have the result that despite the stronger H-F bond the combination of forming the OH bond and formation of better solvation gives rise to a more stable solution and a greater heat of neutralization

  • Suman Kumar Best Answer

    I must admit I didn’t know the facts before reading the question and was at first doubtful so had to look them up. I already knew that when fluorine is involved the Chemistry is strange at best. Thanks for the question I think I have thought out the answer

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    Dinesh khalmaniya 1

    hope this will help you 🙏

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    ok sir thanks and set for late reply

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    please accept the answer

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    ok sir

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    Dinesh khalmaniya 1

    https://doubtnut.com/question-answer-chemistry/for-neutralisation-of-hf-naoh-rarr-naf-h2o-heat-released-during-neutralisation-is-12003336

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    Priyanshu kumar

    so always for strong acid and base the enthalpy of neutrlaisation always remain constant

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    Priyanshu kumar

    so lastly the reaction remains as H+ + OH- = H20

  • comment-profile-img>
    Priyanshu kumar

    The enthalpy of neutralization of any strong acid and strong base is always constant, i.e. 57.1 kJ because both the acid and base undergo complete ionization.

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    Since Dissociation of hydrofluoric acid produces F- and H+ since size of F- is small so it is extensively hydrated which releases large amount of energy(known as hydration energy) which account for its higher neutralizations enthalpy than that of strong acids.

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    most of the weak acids have larger size of anionic part but in HF the size of F- is small so it is hydrated more and hydration energy play its role here...so the enthalpy of neutralisation comes out to be more than 13.7 kcal/mole(-57.1kj/mole).

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    got shweta??I think u understand this whole concept behind this...

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    sry sir for late reply

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    I got it sir

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    ok shweta please accept it if you satisfy

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    ok sir

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