Anku Asked a Question
October 6, 2020 8:25 pmpts 30 pts
pls just show 1 or 2 steps...i am getting confused . . . . . .. . . . . . .
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  • Deepak singh thankyou
    I.e Z2, Z3,Z4,Z6,Z8,Z12,Z24
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  • Deepak singh Best Answer
    since Z24 is cyclic group , So all divisors of 24 will be cyclic subgroup if any doubt then ask
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    Anku
    sir is this valid if there had been Z24+
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