Anku 1 Asked a Question
November 12, 2021 4:10 pmpts 30 pts
pls tell mistake in my explanation for option d. . . .. .. . . . . . . . . . . . . . . . . . . .
  • 2 Answer(s)
  • 0 Likes
  • 2 Comments
  • Shares
  • Navdeep goyal 1 thankyou
    check
    • cropped2690264292634432686.jpg
    Likes(1) Reply(0)
  • Ishu 1 Best Answer
    G is not abelian bcoz N. M≠M.N so G/Z is not abelian therefore G/Z is isomorphic to S3
    Likes(1) Reply(8)
    Anku 1
    but if G/Z will be isomorphic to s3 then G/Z becomes cyclic so by theorem G must be abelian which is contradiction as G is non abelian . so how can it be isomorphic to S3
Head Office :
MPA 44, 2nd floor, Rangbari Main Road,
Mahaveer Nagar II, Kota (Raj.) – 324005

Corporate Office:
212, F-1, 2nd Floor, Evershine Tower,
Amrapali Marg,
Vaishali Nagar, Jaipur (Raj.) – 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com