Anku posted an Question
November 25, 2021 • 23:37 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Pls tell my mistake in explanation..... .

pls tell my mistake .... . . . . . . . . . . . . . .. . . .. . .. . . . . .. .

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  • Anonymous User Best Answer

    S3 is a group of order 6 1,2,3 are divisor of 6 A3 is unique subgroup of S3 of order 3 but S3 is not cyclic

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    what's ur dabut

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    sir it was mentioned this statement is true....so I got confused

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    if you take for every divisor then G is cyclic G={1,-1,-i,I} is a group of order 4 {e} ,H={1,-1} unique subgroup of order 1,2 and G is cyclic in S3 2 order subgroup not unique but 3 order unique

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    sir but for every divisor of 6 there exist unique subgroup in S3

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    sir i was thinking like this

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    2 order subgroup are 3 not unique

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    G={1,-1,-i,I} is a group of order {e} ,H={1,-1} unique subgroup of order 1,2 and G is cyclic its every subgroup unique

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    statement for every divisor

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    ok sir understood now

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