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Anonymous User Best Answer
S3 is a group of order 6 1,2,3 are divisor of 6 A3 is unique subgroup of S3 of order 3 but S3 is not cyclic
what's ur dabut
sir it was mentioned this statement is true....so I got confused
if you take for every divisor then G is cyclic G={1,-1,-i,I} is a group of order 4 {e} ,H={1,-1} unique subgroup of order 1,2 and G is cyclic in S3 2 order subgroup not unique but 3 order unique
sir but for every divisor of 6 there exist unique subgroup in S3
sir i was thinking like this
2 order subgroup are 3 not unique
G={1,-1,-i,I} is a group of order {e} ,H={1,-1} unique subgroup of order 1,2 and G is cyclic its every subgroup unique
statement for every divisor
ok sir understood now