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Shweta Thakur posted an Question

June 04, 2021 • 18:20 pm

30 points

IIT JAM
Chemistry (CY)

Plz check... $31nmedt odd non a w on fanam

$31nmedt Odd non a w On fanaM igzigztusfu lhxoydoyditstisyiskd

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Vicky Sharma

Aromatic
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Pinky chaudhary

look at this
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Dinesh khalmaniya 1 Best Answer

shweta it is aromatic because three double bonds are in conjunction makes it aromatic. and negative charge is present as localised sp2 hybrid orbital so do not takes part in the conjunction
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negative charge mean lone pair
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yes, lone pair
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ok
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sir ik Baar draw krke bta do
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aise Hoga siry ye
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kya draw krna he??
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...ye sp3 hoga
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H nhi ayega, or sp2 hybridisation hoga, because lone pair localised he so hybridisation me count krege
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Priyanshu kumar

Its existence is unstable. If resonance was possible, once carbon would have 2 pi bonds and 2 sigma bonds, which means that particular carbon would be sp hybrid. It's orbitals would require 180 angle which is not possible for benzene ring to provide(only 120 is possible because it's a hexagon and all) And this negative charge with have a significant repulsion from the conjugated electrons. So this negative charge is unstable.
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sir plz expalin kr do draw krke
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sir
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negative charge mean lone pair
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shweta...bs ek baar resonance hone se hi continous 2 pi bond ho jayega...unstable sp hybridized
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...ye Dekho
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condition satisfy nahi na ho rhe hai...double bond hai sp2 hybridized hona hai...fr negative charge hai resonance me jayenge...2 pi bond honge...sp hybridized again condition not satisfied..so this is not possible
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4 bond hi carbon bna sakte hai fr lone pair...not possible
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.....
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shweta here double bond is also there na...
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thanku
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