Shweta Thakur posted an Question
June 03, 2021 โ€ข 19:41 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Plz check for aromatic compound. nh r 4n 6n h

NH r 4n 6n H hdhdgsfsgdgdhdhdhdnfkdkf jfjdhdojdhdjdkvjffjfj

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    Priyanshu kumar best-answer

    yes shweta correct ๐Ÿ‘๐Ÿ‘... double bond- empty p orbital-double bond conjugation

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    Dinesh khalmaniya 1 Best Answer

    yes absolutely correct ๐Ÿ‘๐Ÿ™‚ EC of B = 2s2,2p1 hybridisation = sp2 here Pz orbital do not take part in the hybridisation so can accept electron and take part in the resonance. in this case 3 double bond + B electrons 3ร—2 + 0 = 6 pi e aromatic

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