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Shweta Thakur posted an Question
July 02, 2020 • 18:13 pm
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30 points
30 points
- IIT JAM
- Chemistry (CY)
Plz check this
AR - 2Audaa) Aoheu OCCu in One t C r eudhly & tmatiou adaud Jhot be in eletant el 8tat heu Only we au cuoe 7hs C.Soudad Gutshs onmation 8 cle in rest &tabk ovm is O C ohuu tuuthafy , me cu cb dud Hatan is Jion en matoh
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Suman Kumar Best Answer
The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states. The standard pressure value p⦵ = 105 Pa (= 100 kPa = 1 bar)
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yes I know mam
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but I get confused
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I know all about Hess law and this formula
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What is your confusion Dear
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mam I am sending u the question here only plz check this
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Suman Kumar
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For example, the standard enthalpy of formation of carbon dioxide would be the enthalpy of the following reaction under the above conditions: C(s, graphite) + O2(g) → CO2(g) All elements are written in their standard states, and one mole of product is formed. This is true for all enthalpies of formation.
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Priyanshu kumar
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https://chem.libretexts.org/Bookshelves/General_Chemistry/Map%3A_Chemistry_-_The_Central_Science_(Brown_et_al.)/05._Thermochemistry/5.7%3A_Enthalpies_of_Formation see this shweta..is you get any help from there or not,check and say??
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sir check the points which I have written
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yes shweta when the reactant is present in their elemental state then enthalpy of formation is 0
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Priyanshu kumar
what is your doubt in this??
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Shweta thakur
can I use here that formula (product -reactnt enthalpies) other than Hess law but