Plz check this ..i m not getting correct answer .. col x i3 6ox123 zxn ok a a 513 s 13 o x 2ox2-o x -42-1s 2-43 xt4. st el2x

sir I a not getting no of ions present on edge

also tell can we use that density formula ..... because here spacing is given not edge lentg

you can calculate using formula which I've you already

yes, check my formula

I didn't get

plz explain spacing again

shweta as the edge length comes out to be 2.138cm and given Lif is present at a spacing of 2.10 A°so actually for no.of ions at edge length= edge length divided by spacing

spacing is not equal to edge length right

yess

but sir here spacing is given what's that

it's edge length

you know n= N/Na...So Na=N/n

yes sir

sir ...plz do by direct formula density

as I have used in my solution......

shweta here Lif is present at a spacing of 2.01 angstrom ..so directly it doesn't comes always...

edge length is given

alteady

r*

I have used direct density formula for finding Avogadro no.

here I m not getting answer

directly you can't proceed...because at one edge you have to find...because spacing is also given

wait i m providing you written solution

tok

sir

plz use direct density formula

I think for lif we have to multiply internuclear dist..by 2

shweta you can't proceed directly by this formula...as in ques spacing is also given

sir I have direct formula of density

yes wait..

for lif. . ..we have to multiply internuclear distance by 2 ?

if I multiply by 2 with internuc.distance then I get correct answer but why we have to multiply with 2

wait I'll provide you written solution. but still I'm not at home

ok sir