Shweta Thakur posted an Question
July 08, 2020 • 00:48 am 30 points
  • IIT JAM
  • Chemistry (CY)

Plz expalin this question again i m not getting the concept of spacing... 6.04 x 103 ex. 10. the density f a particular crystal of li

=6.04 x 103 Ex. 10. The density f a particular crystal of LiF is 2.65 g/cc. X-ray analysis show length of gold atoms that Li' and F 1onS are arranged in a cubic array at a spacing of 2.01 A. From these data calculate the apparent Avogadro costant. Solution: See Example 29, Chapter 1.

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    Ashutosh singh

    No, Shweta.

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    Some questions just want to understand your depth of knowledge about it..rather than being formula based..we use formula for atoms, not molecules... please note it down! That density formula is not applicable for molecules, Shweta!

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    In this question, you have to devise to your practical knowledge of finding the edge length...'cc' was the catching point.

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    really sir for molecules we can't use density formuka

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    why

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    Because, if you look at the density formula, it has 'M' in it, which is atomic mass..you tell me, in molecules like LiF or CaF2 what will you take 'M'? it's not possible.

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    sir we take its molar mass for lif it's 25.6 grampermole

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    I send u a picture there they have used

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    this sir

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    Dear Shweta, here it is mentioned that CsCl has cubic structure..and we already know that CsCl has BCC type structure, where Cs is assumed to be at centre and Cl is at the corners...so, the overall contribution of Cs is 1 and Cl is 1 in a cubic crystal...that's why they have taken simply the molecular mass.

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    Ashutosh singh

    Hey Shweta, refer this!

    cropped2121167341.jpg
    cropped1099690637.jpg
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    ok sir but sir here can't we use density direct formula

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    i am confused in spacing and edge length here spacing is given plz give explanation for thos

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    Priyanshu kumar Best Answer

    https://youtu.be/DfIKC357Cm4 correlate this with this vieeo explanation

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    Priyanshu kumar best-answer

    see as there is spacing between atoms..so the edge length of cube is not same as the LiF

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    Priyanshu kumar best-answer

    see this

    cropped5909672459007468679.jpg
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    got shweta here lif is placed on the edge length at a gap of 2.01 A ...

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    so you can find the no of ions on edge length = edge length/spacing

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