Shweta Thakur posted an Question
October 26, 2020 • 00:46 am 30 points
  • IIT JAM
  • Chemistry (CY)

Plz expalin this question and check my solution... the decrease in a of water in 107 m hci solution would be (25°c) a. 48.2 % b. 58.2 9%

The decrease in a of water in 107 M HCI solution would be (25°C) A. 48.2 % B. 58.2 9%

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    Priyanshu kumar Best Answer

    What's your doubt shweta....here first you find the degree of dissociation of water and then find the degree of dissociation when there is 10^-7 M HCL....and find the decrease in alpha in percentage

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    what's your doubt in this solution

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    sir we have to calculate dod of water

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    yes then you find na decrease

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    hai

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    sir

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    why are u taking HCl

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    hcl me dene pe kitta decrease hua wo nikalna hai na

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    first pure water ka nikale then hcl ke sath nikale

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    I have got alpha this

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    yes right

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    iske baad

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    kya krun

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    net decrease kaise

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    shweta once see my solution....

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    this is for pure water...

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    total h+ means

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    H20 ke case main bhi u took 1 * 10 ^ -7

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    means H+ from h20 and hcl

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    hcl ka bhi 10^-7 diya hai na

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    sir h2o Ka kyun lita 10 ^ -7

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    y**

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    ionic products me hote hai na h+ or oh- 10^-7

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    aa gya samagh Maine ache se solution check kiya

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    😊👍

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    alpha = square root(kw / c ) hota but aapne concentration Vali term likhi ni

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    ??

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    Jo square root krke Likha m asking that

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    alpha= sqrt(dissociation constant/ molarity of pure water)

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    sir

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