Shweta Thakur posted an Question
September 17, 2020 • 01:19 am 30 points
  • IIT JAM
  • Chemistry (CY)

Plz expalin this question.... plziabatic reversible expansion. taking monoatomic gas in one case and a diatomic gas in the second case. in

Two separate experiments were carried out involving adiabatic reversible expansion. taking monoatomic gas in one case and a diatomic gas in the second case. In each case. the initial temperature was and expansion was from volume V, to volume VThe final temperatures attained were T for monoatomic gas and To for diatomic gas. hen a) TTo b) TTo TT dTTT 00:00:07

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    Priyanshu kumar Best Answer

    check this

    cropped1643784148495215713.jpg
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    Option B

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    sir monoatomic gas Ka temperature km kyun Hoya diatomic

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    se

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    Tm and Td ka relation derive kiye hai suppose maan ke...kyunki expansion ka case h so V2=10V1 maane h yha pe...to Tm and Td ka relation

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    ok sir

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    sir Gama ka temperature ke sath kya relation hai

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    adiabatic relations sare yaad h??

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    yrs

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    yes

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    toh us se compare kr sakti tm

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    sir

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    like TV^y-1 constant

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    sir ye solution samagh ni aaya

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    koi easy way ni hai

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    isme kya prob aaya easy to hai...koi specific part jha dikkat ho??

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    ab kabhi aayenge xam me to tm direct tick kr sakti ise

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    sir graph samjha skte ho

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    se**

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    mathematically any problem??....here temp part so overall by graph comparison also gets bit difficult

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    no sir

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    ye samagh to aa chuka

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    okk if possible i"ll to explain this by graph also...

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    ok sir

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    as gamaa increases more steeper is the curve therefore monoatomic ke sbse neeche aayega jiski vajah se uska temperature km hoga

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    let me check

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    shweta this approach is right

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    ok sir

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    sir

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