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Suman Kumar
Sourav are you there
yes sir
I hope you know work done in reversible expansion is greater than irreversible expansion
yes sir
I am telling just about magnitude as work done is -ve in expansion
Then you will also accept that expansion leads to cooling
Sourav please ask if you get stuck
im asking why rev temp is less than irr temp
for adiabatic
please answer my question. I am getting to your question
yes sir.. adiabatic exp causes cooling
if more work is done in reversible work then it will cause more cooling.
yes sir, i get your answer what are you trying to say.. i was pretty much cleared about this thing but then i came across one article.. can you check https://www.quora.com/Why-does-temperature-decrease-more-in-adiabatic-irreversible-expansion-than-in-adiabatic-reversible-expansion/answer/Nikhil-Kashyap-32?ch=10&share=155fd5af&srid=8hHwr
you are saying more work more cooling, so rev temp must be less than irr work.. I completely agree.. But then i saw that one
yes Sourav correct
i am looking at it please wait
did you check it sir?
please wait
There is a flaw in it Sourav
Sourav are you there
yes sir.. plz continue
sir you there?