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Shweta thakur Asked a Question
August 20, 2020 8:52 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

Plz explain 4th question... te +0, ()= co (g) at 298 k and 1 atm, ah =- 264lb if the molar

1S T44U ca 4U calories per mole t suue, find nd Au. 64Clfme (1440 cal 4/For the reaction, Cgraphite +0, ()= CO (g) at 298 K and 1 atm, AH =- 264lb If the molar volume of graphite is 0-0053 litre, calculate AU. -26712 cal 5. One mole of an ideal gas at 300 K expands isath 20 litres. Calculata
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  • Priyanshu kumar Best Answer
    check this shweta👇
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    Priyanshu kumar
    please ask if any doubt in this😊
  • Dinesh khalmaniya thankyou
    solution
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    Dinesh khalmaniya
    got it??
  • Amol
    Hope this helps
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  • Dinesh khalmaniya
    hope this helps you 🙏 i
    Likes(0) Reply(0)
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