IIT JAM
Shweta thakur Asked a Question
May 5, 2021 4:18 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

Plz explain second part... dilute sulphuric acid solution were con

IUWlng fon owng Ior 5 hours hours ? WL. Cu=637S4). 11. (a) Two electrolytic cells containing silver nitrate souution and dilute sulphuric acid solution were connected in series. A steady current of 2.5 amp was passed through them till1-078 g of silver was deposited (Ag = 107-8 g mol, 1 F= 96500 C] (1) How much electricity was consumed ? (What was the weight of oxygen gas liberated ? ges af
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  • Dinesh khalmaniya Best Answer
    solution
    • cropped6915939732993310130.jpg
    Likes(0) Reply(3)
    Shweta thakur
    oxygen ke case main bhi 0.01 f kaise aaya
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