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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Shweta Thakur posted an Question
July 24, 2020 • 18:57 pm
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30 points
30 points
- IIT JAM
- Chemistry (CY)
Plz explain the encircled b part deal gas expands isotherr 25c from a volume of 10
S226837y Ex 51 (a) What is the change in entropy of the gas? (i) (ip) What is the change in tibly by simply opening a stopcith the surroundings. (i) W=0. (Pext=0) as we expect entropy to increase in an irreversible proce (iv) ASu =0. e entropy of the system plus surroundings increases by 576/K
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Priyanshu kumar Best Answer
read this example- Imagine an ideal gas confined to a 1-L flask at 1 atm pressure. The flask is connected by a closed stopcock to another 1-L flask, which is evacuated. Now suppose the stopcock is opened while keeping the system at a constant temperature. Then ,the gas will spontaneously expand into the second flask until the pressure is 0.5 atm in both flasks. During this constant temperature, or isothermal expansion into a vacuum, the gas does no work (w = 0) and no heat is transferred between the system and surroundings (q = 0).
now got it shweta??
S is a state function so it doesn't change...as Pext is 0 so no work done also no heat is exchange between system and surroundings...delta S surroundings also equal to 0...
thanks 😊
sir cp is also equal to change in enthalpy of product -reactnt .
yes Shweta heat capacity at constant pressure Cp= DelH/ DelT
also called kirchoffs law at constant pressure
ok sir