Shweta thakur Asked a Question
March 23, 2021 4:20 pmpts 30 pts
win equations (13), (18) and (19), 1ndian b)Irreversible Adiabatic Expansion. AS n the case of irreversible isothermal expansion, expressions for Two cases of expansion are derived below: ) For free expansion. Here, Popp0 dw=-PoDn dV= 0 But dU= öw Refer to Eqn. (1)} dU=0 Further for an ideal gas, Uis a function of temperature and as dU= 0, this means that temperature of the gas remains constant after expansion, i.e., dT= 0 dH= d (U+ P) = dU+ d(PV) dU+ d(RT) = dU-+RdT= 0 +0 =0 Fora fiite change, the expressions forw, AUand AH will be W 0, AU =0, AT=0, AH=0 .20) These expressions are same as for isothermal free expansion. Hence, we conclude thatfor free expansion, uions are identical.
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  • Achyut ranjan gogoi
    yes in free expansion, external pressure is always zero it doesn't variate.
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    Shweta thakur
    sir I m asking the encircled part expansion to I know
  • Achyut ranjan gogoi
    what do u mean by finite process?
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    Shweta thakur
    it means the values are fixed not variable
  • Achyut ranjan gogoi Best Answer
    free expansion is a case of vaccum in which pressure is zero . if pressure is zero then work done= -pdv and w=0. ∆U= q+w by first law for adiabatic q=0 and hence ∆U=0. ∆H = ∆U+ ∆(P...
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    Shweta thakur
    sir plz explain for finite process
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