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Shweta Thakur posted an Question
October 17, 2020 • 21:29 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Plz explain the question. t of radium sulphate (raso4) is 4x 10-1. calculate the solubility in (a) pure water (b) 0-10 m na,so4. calculate answers l

=4f 7.Given that the solubility product of radium sulphate (RaSO4) is 4x 10-1. Calculate the solubility in (a) pure water (b) 0-10 M Na,SO4. Calculate ANSWERS L1.26x 10 mol L- 2.3.5 x 104 5.S (ONi(OH)) = 58 x 10 M, S (AgCN) = 7-8 x 10 M, Ni (OH), is more soluble 6.20 x 1013 M 3. 5 x 10ll mol L- 4. 1-0 x 10- mol L 7.666 x 10 mol L-1, 4 x 10-10 mol L- on for HINTS FOR DIFFICULT PROBLEMS

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  • Suman Kumar

    https://doubtnut.com/minute-question-answer/solubility-product-of-radium-sulphate-is-4xx10-1-what-will-be-the-solubility-of-ra2-in-010-m-naso4--23681864

  • Shweta thakur

    I have done this

    cropped5948346951110314130.jpg
    eduncle-logo-app

    1st one is right...calculate upto the final ans

    eduncle-logo-app

    In 2nd one Na2SO4 will completely ionise so 2Na+=2×0.1 and SO42-= 0.1

    eduncle-logo-app

    now so42- is common ion so solubility of so42- = s+0.1 which is equal to 0.1 as s is very very small in comparison to 0.1 ..

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    Final answer of second part = s× 0.1= ksp... ksp is given now solve for s

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